Abstract
Let R be an associative ring with 1, which is not commutative. Assume that any non-zero commutator v ∈ R satisfies: v2 is in the center of R and v is not a zero-divisor. (Note that our assumptions do not include finite dimensionality.) We prove that R has no zero divisors, and that if char(R) 6= 2, then the localization of R at its center is a quaternion division algebra.
Original language | English GB |
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State | Published - 21 Jul 2021 |
Keywords
- math.RA
- Primary: 12E15